Using Command Prompt to execute a java file

Question

The problem I'm currently having is that I am trying to execute a java file using command prompt, I understand the PATH being set to the jdk's file. Though my java file contains libraries and has to import the libraries, how would I ' import the libraries ' when it runs?

Sample command : javac ClassName.java 1 1 1

When it executes it errors on the imports so what should I do?

Does this help? http://stackoverflow.com/a/2817176/278405 – cychoi Apr 18 '14 at 00:14 — cychoi, Apr 18 '14 at 00:14

score 0 · Answer 1 · answered Apr 18 '14 at 00:08

0

Several issues here:

Are you compiling or executing? javac is the compiler. java is the runtime virtual machine.
ClassName.java is source. ClassName.class is the compiled bytecode run by java.
As a general rule, your environment should contain the variable JAVA_HOME, and that should point at the directory where the JDK resides on your computer.

answered Apr 18 '14 at 00:08

Kode Charlie

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1. Executing 2. I'm just executing the source. 3. And the imports are external .jar files, not java libraries. – wateraura Apr 18 '14 at 00:12
You cannot execute the source. You can compile the source. – cychoi Apr 18 '14 at 00:13

score 0 · Accepted Answer · answered Apr 18 '14 at 03:38

The .jar files are Java "libraries". What you need is something like:

> javac ClassName.java
> java -cp Library1.jar:Library2.jar ClassName.class

The first line (javac) compiles the Java code into a class file. The second line runs the compiled class. The '-cp' option sets the CLASSPATH (makes the code in the jar files available at runtime). Note: the exact syntax will depend on if you are using Mac OSX/Linux or Windows. Windows uses the ';' character to separate the jar file names.

Using Command Prompt to execute a java file

2 Answers2