Delete single Char in String java

Question

I have an array of String, and the items are like : 02:11, 11:12..
I want to delete the 0 in first position.

if (orari[i].substring(0,0) == "0") {
   orari[i] = orari[i].substring(1,4);
}

It doesn't work, why?

do like below: if (orari[i].charAt(0) == '0') { orari[i] = orari[i].substring(1); } — Gundamaiah, Apr 18 '14 at 09:23

score 2 · Accepted Answer · answered Apr 18 '14 at 09:16

Firstly your substring bounds are faulty. 0, 0 means 0 length string. That will not get you first character. You should use 0, 1. And then use equals() method for String comparison:

if (orari[i].substring(0,1).equals("0"))

Also, you can avoid that substring in if condition by using charAt() method:

if (orari[i].charAt(0) == '0')

score 2 · Answer 2 · answered Apr 18 '14 at 09:16

2

Because it should be like this:

if (orari[i].charAt(0) == '0') {
   orari[i] = orari[i].substring(1,4);
}

answered Apr 18 '14 at 09:16

Andremoniy

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score 0 · Answer 3 · answered Apr 18 '14 at 09:16

0

if (orari[i].substring(0,0).equals("0")) {
   orari[i] = orari[i].substring(1,4);
}

use equals() to compare string, not ==

answered Apr 18 '14 at 09:16

Eric

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Delete single Char in String java

3 Answers3