Initialization discards qualifiers from pointer target type

Question

I'm trying to print the list of a singly linked list that I referred to in link text. It works, but I do get the compiler warnings:

Initialization discards qualifiers from pointer target type

(on declaration of start = head) and

return discards qualifiers from pointer target type

(on return statement) in this code:

/* Prints singly linked list and returns head pointer */
LIST *PrintList(const LIST *head) 
{
    LIST *start = head;

    for (; start != NULL; start = start->next)
        printf("%15s %d ea\n", head->str, head->count);

    return head;
}

I am using XCode. Any thoughts?

Answer 1

It's this part:

LIST *start = head;

The parameter for the function is a pointer to a constant, const LIST *head; this means you cannot change what it is pointing to. However, the pointer above is to non-const; you could dereference it and change it.

It needs to be const as well:

const LIST *start = head;

The same applies to your return type.

---

All the compiler is saying is: "Hey, you said to the caller 'I won't change anything', but you're opening up opportunities for that."

Answer 2

In following function, would get the warning that you encountered with.

void test(const char *str) {
  char *s = str;
}

There are 3 choices:

1. Remove the const modifier of param:

   void test(char *str) {
     char *s = str;
   }
   

2. Declare the target variable also as const:

   void test(const char *str) {
     const char *s = str;
   }
   

3. Use a type convert:

   void test(const char *str) {
     char *s = (char *)str;
   }