I have a problem trying to find and get and array from a bi dimensional array in python. I don't pretend to use a for structure for example in order to get this. Someone knows how to get this array in just one or a few lines of code?.
Thanks.
There is an example:
my_dimensional_array = [(1,'a'),(1,'b'),(2,'c'))]
I need to return
my_single_array_from_1 = [(1,'a'),(1,'b')]
If you just want to exclude the last element, you can use slicing like this
my_dimensional_array = [(1, 'a'), (1, 'b'), (2, 'c')]
print my_dimensional_array[:-1]
# [(1, 'a'), (1, 'b')]
You could use a list comprehension to select those elements in my_dimensional_array whose first value equals 1:
In [16]: my_dimensional_array = [(1,'a'),(1,'b'),(2,'c')]
In [17]: [item for item in my_dimensional_array if item[0]==1]
Out[17]: [(1, 'a'), (1, 'b')]
You can do that as:
result = [(i,j) for i,j in my_dimensional_array if i==1]
