Search through a string and return specific text android

Question

Hi how can i return Grapes from the string below, i want to search through a string and return a text in the middle of the string after four character and discard the rest of the text.

String grapes = "2 x Grapes @Walmart";

you want `Grapes` , is at always after 4 characters ? , there may be a case when you buy more grapes and the string becomes 10 X Grapes, i.e. after 5 characters — aelor, Apr 22 '14 at 13:51
So you want... what? The third word? The middle word? The first word after the first 4 characters? What should `2x Grapes foo` return? — Robin, Apr 22 '14 at 13:52
Thanks after 4 or 5 characters and discard the remaining text — Junius L, Apr 22 '14 at 13:53
@Robin i'm completely new android and java can you please clarify the split statement — Junius L, Apr 22 '14 at 13:59
You can read more about it here: http://stackoverflow.com/questions/3481828/how-to-split-a-string-in-java . You don't need regex for this task, splitting on whitespace will give you an array with each word in it. — Robin, Apr 22 '14 at 14:00

score 1 · Accepted Answer · answered Apr 22 '14 at 14:23

1

Thanks for helping me guys the code below worked

String grapes = "2 x Grapes @Walmart";
String[] split = grapes.split("\\s+");
String fsplit = split[2];

answered Apr 22 '14 at 14:23

Junius L

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Good job. Don't forget to mark your own answer as accepted to close your question. – Robin Apr 22 '14 at 14:26

score 0 · Answer 2 · answered Apr 22 '14 at 13:59

my suggestion will be not to use a regex for this . But just in case you find no other way round, use this :

(\w+\s){3}

you will get the third word in the first backreference. \1 or $1 whichever supports your compiler

demo here : http://regex101.com/r/jB5nN0

score -1 · Answer 3 · answered Apr 22 '14 at 14:01

This may help you:

^[\\d]+\\sx\\s(.*?)\\s+.*?$

Explanation:

Assert position at the beginning of a line (at beginning of the string or after a line break character) «^»
Match a single digit 0..9 «[\d]+»
   Between one and unlimited times, as many times as possible, giving back as needed (greedy) «+»
Match a single character that is a “whitespace character” (spaces, tabs, and line breaks) «\s»
Match the character “x” literally «x»
Match a single character that is a “whitespace character” (spaces, tabs, and line breaks) «\s»
Match the regular expression below and capture its match into backreference number 1 «(.*?)»
   Match any single character that is not a line break character «.*?»
      Between zero and unlimited times, as few times as possible, expanding as needed (lazy) «*?»
Match a single character that is a “whitespace character” (spaces, tabs, and line breaks) «\s+»
   Between one and unlimited times, as many times as possible, giving back as needed (greedy) «+»
Match any single character that is not a line break character «.*?»
   Between zero and unlimited times, as few times as possible, expanding as needed (lazy) «*?»
Assert position at the end of a line (at the end of the string or before a line break character) «$»

Search through a string and return specific text android

3 Answers3