How does java calculate this?
int number = (int) Long.parseLong("F9DFF755", 16);
Long.parseLong("F9DFF755", 16); == 4192204629 (too big to be stored by an int)
Casted to int : -102762667
How does java force a long to fit into an int?
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grepsedawk
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6It doesn't. The `int` just overflows. – Boris the Spider Apr 22 '14 at 21:02
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it takes the right-most 32 bits, discarding the other 32 bits. This means that bit 32 from the original number (counting from the right) becomes the new sign bit. – Dave Apr 22 '14 at 21:02
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Casting a long to an int simply consist in keeping the last 32 bits of the long, and ignoring the first 32 bits.
JB Nizet
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