increment operator in c array handling

Asked Apr 26 '14 at 17:17

Active Apr 26 '14 at 17:17

Viewed 37 times

#include<stdio.h>

void main()
{
  int a[10]={};
  int n=2,i;
  //a[4]=0;
  for(i=0;i<10;i++)
    printf("%d",a[i]);
  printf("\n");
  a[++n] = n++;
  for(i=0;i<10;i++)
    printf("%d",a[i]);
}

As per my understanding this should assign a value of 2 to a[4] but the gcc compiled exe prints 3 to the a[4]. What is wrong with my understanding? Please elaborate.

thanks, muru

asked Apr 26 '14 at 17:17

muru

@luker it sets all the values in array to 0 – muru Apr 26 '14 at 17:24
important is you need to learn sequence point. – Grijesh Chauhan Apr 26 '14 at 17:25
You need `int a[10]={0};` for it to be standard C I think, @muru. – Mat Apr 26 '14 at 17:26
thanks all for the redirection – muru Apr 26 '14 at 17:33

increment operator in c array handling

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