Create a text menu in Python3x that is always available

Question

I am new to python and learning quickly. Thank you all for the help.

I am attempting to create a text menu that will always run in the background of a storytelling text rpg. I have searched and cannot find an explanation of how to create an "always on" menu or how one would work.

I would like the player to be able to hit "m" at any time in the game and have the menu prompt show up.

So far, I have created a "userinput" function as well as a "menu" function that will be deployed each time the game prompts the user/player for input.

def menu():
    print('Press "1" for map >>> "2" for stats >>> "3" for exit')
    choice = input()
    if choice == '1':
        print('map needs to be made and shown')
    elif choice == '2':
        print('stats need to be made and assinged to choice 2 in def menu')
    elif choice == '3':
        print('You are exiting the menu. Press "M" at any time to return to the menu')
        return
    else:
        print('I did not recognize your command')
        menu()

def userinput():
    print('Press 1 to attack an enemy >>> 2 to search a room >>> 3 to exit game')
    print('Press "M" for menu at any time')
    inputvalue = input()
    if inputvalue == 'm':
        menu()
    elif inputvalue == '1':
        print('attack function here')
    elif inputvalue == '2':
        print('search function here')
    elif inputvalue == '3':
        exit
    else:
        userinput()

This does not appear to be an ideal solution because the user cannot choose to view a map or exit the game at any time they want.

Is there a way to have a menu always running in the background?

I thought of using a while loop that would never close and all of the game would be held within that while loop but that doesn't seem economical by any means.

Any thoughts or help would be appreciated.

There isn't really a generic way to do it. You'll basically have to add a hook to every menu that takes you back to the primary one. There are some tools like [cmd](https://docs.python.org/2/library/cmd.html) that might make doing that easier, but it's still basically a [state-machine](https://www.google.com/search?q=state+machine+python&oq=state+machine+python&aqs=chrome..69i57j0l5.6607j0j4&sourceid=chrome&es_sm=91&ie=UTF-8) problem. — aruisdante, Apr 26 '14 at 21:36
You say that you want it so "the user can choose to view a map or exit the game at any time they want" (paraphrased). But they can? m, 1 shows the map, 3 and also m, 3 exits the game. Do you want 1 key press controls for everything? (if so you've overloaded 1 and 2). — demented hedgehog, Apr 26 '14 at 23:19

score 0 · Accepted Answer · edited May 23 '17 at 11:49

I took a stab at it. This is perhaps not the best structure for doing what you're looking for but I don't want my reply to get too complicated.

The "standard" approach for anything with a UI is to separate the model, the view and the control. Check out MVC architecture online. While it adds complexity at the start it makes life much simpler in the long run for anything with a non trivial UI.

Other points of note are:

you're not stripping whitespace from your input (potentially problematic "3 " won't do what you want)
you're input is case sensitive (you ask for "M" but check for "m") .. maybe use choice = choice.strip.lower()??
there's a difference between the way raw_input and input work between Python 2 and Python 3 which means your code doesn't work in python 2. What's the difference between raw_input() and input() in python3.x? I've changed my example to use raw_input. You may want to use this work around http://code.activestate.com/recipes/577836-raw_input-for-all-versions-of-python/ near the top of your code for portability.

Some code

# flag we set when we're done
finished = False

def finish():
    # ask the user for confirmation?
    global finished
    finished = True
    return


def handle_menu_input(choice):
    handled = True

    if choice == '1':
        print('map needs to be made and shown')
    elif choice == '2':
        print('stats need to be made and assinged to choice 2 in def menu')
    else:
        handled = False

    return handled

def menu():

    finished_menu = False
    while not finished_menu:

        print('Press "1" for map >>> "2" for stats >>> "3" for exit')
        choice = raw_input() # NOTE: changes behaviour in Python 3!

        if handle_menu_input(choice):
            # done
            pass
        elif choice == '3':
            print('You are exiting the menu. Press "M" at any time to return to the menu')
            finished_menu = True
        else:
            print('I did not recognize your command')
            menu()
    return


def userinput():
    print('Press 1 to attack an enemy >>> 2 to search a room >>> 3 to exit game')
    print('Press "M" for menu at any time')
    choice = raw_input() # NOTE: changes behaviour in Python 3!

    if choice == 'm':
        menu()
    elif choice == '1':
        print('attack function here')
    elif choice == '2':
        print('search function here')
    elif choice == '3':
        finish()

    # elif handle_menu_input(choice):
    #     # delegate menu functions?? ..
    #     # do this if you want to see maps anytime without going through the menu?
    #     # otherwise comment this elif block out.
    #     # (Problem is 1, 2 etc are overloaded)
    #     pass
    else:
        print('I did not recognize your command')
    return


def main():
    # main loop
    while not finished:
        userinput()
    return

if __name__ == "__main__":
    main()

Thank you DH. Your help is appreciated and pointing me in the right direction. — user3570952, May 23 '14 at 04:25

Create a text menu in Python3x that is always available

1 Answers1