Add floating numbers in bash

Question

I'm trying something very easy but all code that I'm trying doesnt work. I need add two float numbers in bash. I'm doing this:

result1=`$CURL -o /dev/null -s -w %{time_total} $url1`
result2=`$CURL -o /dev/null -s -w %{time_total} $url2`
result3=`$CURL -o /dev/null -s -w %{time_total} $url3`
total= `expr $result2 + $result3`

echo $total | $GAWK -F: '{ print "connection_1.value " $1 }'

but in the prompt I'm getting this output:

./http_response_2: line 12: 0,018+0,255: command not found
connection_1.value

I'm trying too do this:

result1=`$CURL -o /dev/null -s -w %{time_total} $url1`
result2=`$CURL -o /dev/null -s -w %{time_total} $url2`
result3=`$CURL -o /dev/null -s -w %{time_total} $url3`
total= `$result2 + $result3 | bc`

getting the same result. Thanks in advance!

replace your last line in the last snippet by: `total=$(bc <<< "$result2+$result3")` — gniourf_gniourf, Apr 28 '14 at 14:11
@fedorqui thanks, but I'm getting this: expr: no integer argument — hcarrasko, Apr 28 '14 at 14:13
Plus, there is comma, not a decimal point in `0,018+0,255`. If it is not a typo, then it should be `total=$(tr ',' '.' <<< "$result2 + $result3" | bc -l)` — anishsane, Apr 28 '14 at 14:14
@gniourf_gniourf with you suggestion I'm getting this error: `(standard_in) 1: syntax error (standard_in) 1: syntax error` — hcarrasko, Apr 28 '14 at 14:15
@anishsane thanks! but the zero is missing, I'm getting this: `connection_2.value .374` — hcarrasko, Apr 28 '14 at 14:18
^^ This can help you: http://stackoverflow.com/questions/8402181/how-do-i-get-bc1-to-print-the-leading-zero — anishsane, Apr 28 '14 at 14:24
That's because you have commas in your numbers. To replace commas with periods: `total=$(bc <<< "${result2//,/.}+${result3//,/.}")` — gniourf_gniourf, Apr 28 '14 at 14:25

score 3 · Accepted Answer · answered Apr 28 '14 at 14:21

3

There are 3 issues:

There should be no space between total= & `
echo missing before $result2 + $result3
There is comma in your input, instead of decimal point.

Fixing all these issues:

total=$(tr ',' '.' <<< "$result2 + $result3" | bc -l)

If you are concerned about the leading 0 before decimal point, try:

total=$(tr ',' '.' <<< "$result2 + $result3" | bc -l | xargs printf "%g")

answered Apr 28 '14 at 14:21

anishsane

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thank you very much master :) `total=$(tr ',' '.' <<< "$result2 + $result3" | bc -l | xargs printf "%g")` solves my problem – hcarrasko Apr 28 '14 at 14:26

score 0 · Answer 2 · answered Mar 04 '18 at 11:02

Instead of replacing commas with dots, don't produce commas in the first place.

They emerge from localization, so use LC_ALL=C as prefix, like:

LC_ALL=C curl -o /dev/null -s -w %{time_total} www.google.com

and abandon the outdated backticks, use $(...) instead:

result1=$(LC_ALL=C $CURL -o /dev/null -s -w %{time_total} $url1)

Add floating numbers in bash

2 Answers2