Doctor program - python

Question

Below is a short doctor program that I am making and this is the start, unfortunately, it doesn't work. Here is the error I receive - TypeError: input expected at most 1 arguments, got 4

least = 0
most = 100

while True:
    try:
        levelofpain = int(input("How much is it hurting on a scale of", (least), "to", (most)))
        while llevelofpain < least or levelofpain > most:
            print ("Please enter a number from", (least), "to", (most))
            levelofpain = int(input("How much is it hurting on a scale of", (least), "to", (most)))
        break
    except ValueError:
        print ("Please enter a number from", (least), "to", (most))

Thanks in advance!

p.s. using python 3.3

score 2 · Answer 1 · answered Apr 29 '14 at 09:09

2

The error message is self-explanatory -- you are passing four arguments to input(...) where it is only accepting one.

The fix is to turn the argument into a single string.

levelofpain = int(input(
    "How much is it hurting on a scale of {} to {}? ".format(least, most)))

answered Apr 29 '14 at 09:09

tripleee

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You could catenate `"string " + str(least) + " more string"` etc but that's hardly an improvement. Why would you want to avoid using a function? Functions are your friends. – tripleee Apr 29 '14 at 10:52
1

`print (str("Please enter a number from", (least), "to", (most)))` – Apr 29 '14 at 15:54

score 0 · Answer 2 · edited May 23 '17 at 10:26

For formatting strings, you probably want to use Python's .format() function. Take a look at this question: String Formatting in Python 3

There are two main methods for formatting strings in Python, the new way using the .format method of the str class, and the old C style method of using the % symbol:

str.format():

"This is a string with the numbers {} and {} and {0}".format(1, 2)

C Style Format (%):

"This is another string with %d %f %d" % (1, 1.5, 2)

I strongly recommend not using the C Style Format, instead use the modern function version. Another way I don't recommend is replacing the input function with your own definition:

old_input = input
def input(*args):
    s = ''.join([str(a) for a in args])
    return old_input(s)

input("This", "is", 1, 2, 3, "a test: ")

@user3584575 The typical method is just to use the `.format()` member of string, but see my edit for two other alternatives. You can also use the method triplee mentioned in his comment. — ilent2, Apr 29 '14 at 12:12

Doctor program - python

2 Answers2