How to not print
in a string but get a newline instead

Question

I'm trying to put 2 lines of sentences into a variable, which will be used to display a popup message (same one that shows using alert()). But when I try to put breaks between them the
tag instead just appears a part of text. Anyway to solve this issue? Below is my code.

$new_error_message = 'Oops, something went wrong! <br/> Your transaction could not be processed.';

Thank you

UPDATE:

I forgot to mention that I'm using 'throw new Phpr_ApplicationException($new_error_message);' to display the message because it's meant to be an error message, not alert().

How are you displaying that text? You say like alert(), but we need more details. You probably want to put a newline character in it instead: \n — Telgin, Apr 30 '14 at 21:54
possible duplicate of [New line in JavaScript alert box](http://stackoverflow.com/questions/1841452/new-line-in-javascript-alert-box) — Anonymous, Apr 30 '14 at 21:55
I am using 'throw new Phpr_ApplicationException($new_error_message);', because it's meant to be an error message. — user3408005, Apr 30 '14 at 21:55
possible duplicate of http://stackoverflow.com/questions/591130/can-i-add-a-br-and-links-to-a-javascript-alert — Anonymous, Apr 30 '14 at 21:56
There's nothing wrong with your code. It prints out in two lines. — Funk Forty Niner, Apr 30 '14 at 22:04
strange.. Your code echos the message, but when I use 'throw new Phpr_ApplicationException($new_error_message);', it just prints br tag.. — user3408005, Apr 30 '14 at 22:50
Ah I see how you're using it now. You can't do that, *period.* @user3408005 You can't modify a core function. — Funk Forty Niner, May 01 '14 at 01:28
Would there be an alternative method of replicating the same popup message? — user3408005, May 01 '14 at 02:39

score 2 · Accepted Answer · answered Apr 30 '14 at 21:55

2

Use the \n escaped character to create a new line in PHP.

$new_error_message = "Oops, something went wrong! \n Your transaction could not be processed.";

Also note that a string that uses escaped characters needs to be in double quotes.

Docs: http://www.php.net/manual/en/language.types.string.php

answered Apr 30 '14 at 21:55

Chris Bier

14,183
17
67
103

Should probably use PHP_EOL constant instead. – Jessica Apr 30 '14 at 21:58
Can you post an example? That seems interesting and a valid way to address the issue – Chris Bier Apr 30 '14 at 21:59
Here's a good question talking about when to use `\n` and when to use `PHP_EOL` http://stackoverflow.com/questions/4975411/when-do-i-use-php-eol-instead-of-n-and-vice-versa-ajax-jquery-client-problem – Chris Bier Apr 30 '14 at 22:00
I'm not sure if you're using that to indicate use it or not, but that link does say for output, and this is output, yes? – Jessica Apr 30 '14 at 22:04
Yes, so it is indeed an option to accomplish the OP's task, and looks like a better option than I posted. Didn't know about it until you mentioned it though, so it's rightfully your answer. I won't post it as my own – Chris Bier May 01 '14 at 15:55

score 0 · Answer 2 · answered Apr 30 '14 at 21:54

0

Instead of <br/> try \n.

answered Apr 30 '14 at 21:54

TheHacksaw

432
2
6

The OP would need to use double quotes on the echo, right now they are using single quotes – Chris Bier Apr 30 '14 at 21:56
I tried that with no success. It just prints \n as it is. – user3408005 Apr 30 '14 at 21:56
1

@user3408005 refer to my answer, you need to use double quotes: `echo "first line \n second line";` – Chris Bier Apr 30 '14 at 21:57
Chris B - I tried that too, but this stubborn thing just doesn't work. It changes \n into a
and shows it in the message. It at least does make a new line though.. – user3408005 Apr 30 '14 at 23:06

score 0 · Answer 3 · edited May 23 '17 at 12:28

0

If it's an alert();, you want to replace the <br /> tag with \n

You can do this in javascript if you like (taken from here):

str = str.replace(/\n/g, '<br />');

edited May 23 '17 at 12:28

Community

1
1

answered Apr 30 '14 at 21:55

Duniyadnd

4,013
1
22
29

How to not print in a string but get a newline instead

3 Answers3

How to not print
in a string but get a newline instead