C++ order of element initialization in aggregate class

Asked Apr 30 '14 at 22:18

Active Apr 30 '14 at 22:36

Viewed 73 times

I know, that in aggregate class

Each array element or non-static class member, in order of array subscript/appearance in the class definition, is copy-initialized from the corresponding clause of the initializer list.

But my question is: can we use previous initialized elements in initialization? Like:

std::array<int, 2> d = { 3, d[0] };

int d[] = {3, d[0]};

Thanks!

edited Apr 30 '14 at 22:36

asked Apr 30 '14 at 22:18

Bikineev

1,685
15
20

I don't _think_ so, but... I don't know – Mooing Duck Apr 30 '14 at 22:20
It seems to work on both Visual Studio and gcc. I wouldn't recommend it though. – jliv902 Apr 30 '14 at 22:37
There's probably a difference between objects with trivial and non-trivial initialization, see [basic.life] and [class.cdtor]. – dyp Apr 30 '14 at 22:42
This is http://www.open-std.org/jtc1/sc22/wg21/docs/cwg_active.html#1343 (see the last note) – Johannes Schaub - litb Apr 30 '14 at 23:49

C++ order of element initialization in aggregate class

0 Answers0