How to use files from source package (what's the path?)

Question

Ok, the title may not be exactly correct, but here is what I mean by that: I have a class with a method that looks like this:

package chess;

import java.io.*;
import sun.audio.*;

public class SoundPlayer

{
  public static void Play(String AudioFile) 

  throws Exception

  {
    // open the sound file as a Java input stream
    InputStream in = new FileInputStream(AudioFile);

    // create an audiostream from the inputstream
    AudioStream audioStream = new AudioStream(in);

    // play the audio clip with the audioplayer class
    AudioPlayer.player.start(audioStream);
  }
}

What I want to do, is to compile a .wav file inside the .jar along all the .java files, and be able to play it with this method. To do this on batch, all I had to do was type the file name, and it used the current directory. I tried that here and it didn't work. So, my final question:

What do I need to type before "/sound.wav" to have my program reffer to it from the source directory? Sorry if I didn't make it clear. I have searched around, but I guess I didn't know what exactly to search for on google, because I didn't find any explanation.

David Xu · Accepted Answer · 2014-05-02T19:16:03.630

3

You can use ClassLoader.getResourceAsStream() for that

example:

 // open the sound file as a Java input stream
InputStream in = SoundPlayer.class.getClassLoader().getResourceAsStream("yoursound.wav");

// create an audiostream from the inputstream
AudioStream audioStream = new AudioStream(in);

// play the audio clip with the audioplayer class
AudioPlayer.player.start(audioStream);

edited May 02 '14 at 19:16

answered May 02 '14 at 19:06

David Xu

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if that works, I'm not understanding how to use it. can you tell me what I would have to input when I call the Play(string) method? – RaKXeR May 02 '14 at 19:14
Updated my answer to help you. – David Xu May 02 '14 at 19:16
that doesnt seem to work :( – RaKXeR May 02 '14 at 19:21
Obviously you have to change the path, so if you put the soundfile in resources/blah.wav, change the string to "/resources/blah.wav" – David Xu May 02 '14 at 19:22
I am not understanding what this method is suppose to do – RaKXeR May 02 '14 at 19:32

score -1 · Answer 2 · answered May 02 '14 at 19:06

-1

If you put your wav files inside your jar, at the root, you should be able to refer to them by its name. I.e

jar
 |-com
    |-your
       |-package
 |-sound.wav

You can access sound.wav on com.your.package.yourclass by referring to it by just its name

answered May 02 '14 at 19:06

perencia

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This might be the start of an answer, but it is incomplete, as you've failed to specify what sort of "refer" would work with "its name" as an argument. – Chris Stratton May 02 '14 at 19:11
Then I'd say this is not an answer, and not useful. – Chris Stratton May 02 '14 at 19:16
What is wrong in what i've said ? The question was how to refer to a sound file inside a jar, if I understood it correctly. The question wasn't that clear also. I don't see why it's not an answer. You should relax. – perencia May 02 '14 at 19:35
It's not an answer because you fair to state an access *mechanism* which would accept the name as an argument. – Chris Stratton May 02 '14 at 19:57
I'd say it to you before. There's no specific _access mechanism_, you can access that file the same as if it was on the file system. You can do `FileInputStream("sound.wav")`. Where that _access mechanism_ was mentioned on the question ? – perencia May 02 '14 at 20:01

How to use files from source package (what's the path?)

2 Answers2