Encapsulation and const issues

Question

I have a problem in a c++ assignment that cannot be solved. Lets say this - the program works only if the membervariable (a pointer to an char-array) i public. But according to the rules it must be private and one should be able to access it through a public member-method.

Here is the definitions:

private:
   char* _strPtr();
   int _strLen;
public:
   const char* getString();

const char* String::getString() {
   return _strPtr;
 }

And here in an overloaded member-function the problem arises

 const String operator+(const String string, const char *ch) {

   String temp;
   strcpy(temp.getString, string.getString());
   strcat(string.getString(), ch);

return temp;

 }

I get error-messages such as

 invalid arguments Candidates are ; unsigned int strlen(const char *)
 invalid arguments Candidates are ; const char* getString()

I cannot see how this could be solved. I have really tried with everything. Would be glad if someone could come with good tips.

As - I said in th beginning - the program works, but after encapsulating the membervariable and putting a const ahead of the function - it doesn't work any more.

enter image description here

Did you mean `temp.getString()` instead of `temp.getString`? — keyser, May 04 '14 at 20:15
@keyser - yes, I changed the code - but the problem persists — user2991252, May 04 '14 at 20:17
Same error? It didn't match the candidate `const char* getString()` now? — keyser, May 04 '14 at 20:18
See [operator overloading](http://stackoverflow.com/questions/4421706/operator-overloading) for good ideas on how to implement `operator +` in terms of a member `operator +=`. — juanchopanza, May 04 '14 at 20:20

score 1 · Answer 1 · answered May 04 '14 at 20:54

1

You are defining char* _strPtr();, which is the definition of a function returning a char*. Probably what you meant was to define char* _strPtr;

answered May 04 '14 at 20:54

vsoftco

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Encapsulation and const issues

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