Enforce variable creation

Question

In c++, I have a class, say T. It is meaningful to construct an object as T t(); but not as T();. Can the second version be blocked?

`T t();` declares a function. It doesn't create a variable. To invoke the default constructor on a new object, you **must not** use parentheses. — zneak, May 06 '14 at 18:58

score -1 · Answer 1 · answered May 06 '14 at 19:10

-1

You can use

T t; // invokes T() implicitly (t object is created on stack)
T* t = new T(); // explicitly (object is created on heap, pointer t to that object is on stack)

But

T t(); // declares function t of a return type T

answered May 06 '14 at 19:10

Nenad

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How is this related to disallowing creating temporary `T`s? – Benjamin Bannier May 06 '14 at 19:13

Enforce variable creation

1 Answers1