Converting String to char when String is a valid char

Question

I am doing socket communication using bluetooth in which I am getting hex values as a variables in string format.

I can write -

char char1= 0x7D;

But somehow if value 0x7D is string then how to convert that to char.

For example, I can't do -

String string1 = "0x7D";
char char1 = (char)string1;

Any approach to do that ?

I want this because I can write to socket with -

char[] uploadCommand2 =  {0x7d, 0x4d, 0x01, 0x00, 0x01, 0xcb};

But can't if 0x7d is a string like --

char[] uploadCommand2 =  {string1, 0x4d, 0x01, 0x00, 0x01, 0xcb};

possible duplicate of [How to convert/parse from String to char in java?](http://stackoverflow.com/questions/7853502/how-to-convert-parse-from-string-to-char-in-java) — Pankaj Kumar, May 07 '14 at 13:30
@UrsulRosu - that would return "0" for him. Not what he wants — dymmeh, May 07 '14 at 13:31
not a duplicate, and I don't understand why this was downvoted. That's a good question, properly asked, with enough information to try and answer it. — njzk2, May 07 '14 at 13:31
@njzk2 Removed close vote. That was for the question before his edit... :) — Pankaj Kumar, May 07 '14 at 13:35

score 3 · Accepted Answer · edited May 23 '17 at 10:32

3

If you strip off the 0x prefix for your hex String representation, you can use Integer.parseInt and cast to char.

See edit below for an alternative (possibly more elegant solution).

String s = "0x7D";
//                  | casting to char
//                  |    | parsing integer ...
//                  |    |                | on stripped off String ...
//                  |    |                |               | with hex radix
System.out.println((char)Integer.parseInt(s.substring(2), 16));

Output

Edit

As njzk2 points out:

System.out.println((char)(int)Integer.decode(s));

... will work as well.

edited May 23 '17 at 10:32

Community

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answered May 07 '14 at 13:32

Mena

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see http://stackoverflow.com/a/11377996/671543 no need to strip the 0x, `decode` does that – njzk2 May 07 '14 at 13:34
@Mena - Isn't it possible without stripping 0x ? Can't I get char `0x7D` ? – sjain May 07 '14 at 14:08
@VedPrakash see my edit, after njzk2's suggestion. The `decode` method will do just that. However you'll need to double cast. – Mena May 07 '14 at 14:11

score 0 · Answer 2 · answered May 07 '14 at 13:32

0

Integer.parseInt(String) returns an Integer representation of the given String from which you can then obtain the character.

answered May 07 '14 at 13:32

schubakah

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score 0 · Answer 3 · answered May 07 '14 at 13:33

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String string1 = "0x7D";
char char1 = (char) Integer.parseInt(string1.substring(2), 16);

Edit: This works, but Integer.decode() is the way to go here (thanks to njzk2).

answered May 07 '14 at 13:33

Gabriel Negut

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Isn't it possible without stripping 0x ? Can't I get char `0x7D` ? – sjain May 07 '14 at 14:10
@VedPrakash: No. The documentation states that the string can only contain `+`, `-` and digits of the specified radix (in this case, `0` - `9`, `a` - `f`, `A` - `F`). – Gabriel Negut May 07 '14 at 14:17

Converting String to char when String is a valid char

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