How to String format urls that contain path parameter

Question

I have the url https://www.someurl.com/v2/path/[PARAM1]?key=[PARAM1]2. I want to do the following

final String URL = "https://www.someurl.com/v2/path/%?key=%";
String val = String.format(URL, "details", "testing");
System.out.println(val);

But I am getting an error

Exception in thread "main" java.util.UnknownFormatConversionException: Conversion = '?'
at java.util.Formatter.checkText(Formatter.java:2547)
at java.util.Formatter.parse(Formatter.java:2533)
at java.util.Formatter.format(Formatter.java:2469)
at java.util.Formatter.format(Formatter.java:2423)
at java.lang.String.format(String.java:2845)
at split.StringStuff.main(StringStuff.java:22)

How might I make it work?

You should consider using URI templates – fge May 15 '14 at 07:08 — fge, May 15 '14 at 07:08

score 3 · Accepted Answer · answered May 15 '14 at 06:27

3

Since the placeholders are for String values, you need to use %s instead of just %.

final String URL = "https://www.someurl.com/v2/path/%s?key=%s";

answered May 15 '14 at 06:27

Rahul

44,383
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score 2 · Answer 2 · answered May 15 '14 at 06:27

2

you should use %s character in format, not just %.

answered May 15 '14 at 06:27

TechnoCat

25
3

How to String format urls that contain path parameter

2 Answers2