PHP Syntax: "or" in "If" Statement

Question

hello I just wanted to check and see if this would be correct PHP syntax:

if ($input == "DeOnTRAY96@localhost"){
echo"
Projects: 1"?>
<br>
<?php     
echo"
Admin: yes
";

}
elseif ($input == NULL){
die("Please enter password.");
}else{
header("Location:Invalidpassword.php");
exit;
}

Right where is says

if($input == "DeOnTRAY96@localhost"){

Could I put

if($input == "DeOnTRAY96@localhost" or "somethingelse"){

And still have it work?

score 0 · Answer 1 · answered May 18 '14 at 16:31

0

You don't want

if($input == "DeOnTRAY96@localhost" or "somethingelse"){

You want

if($input == "DeOnTRAY96@localhost" or $input == "somethingelse"){

I might suggest using === instead of == in this case, as you'd like a type sensitive comparison.

Additionally, for $input == NULL you should use is_null($input). Null is weird in most programming languages, so language specific functions for testing are usually the way to go (rather than comparison)

answered May 18 '14 at 16:31

preinheimer

3,712
20
34

Ok thanks I need to see if you could do that because i wanted to have 2 options that you could type into the password box – user3144705 May 18 '14 at 16:33
The `in_array()` suggestion made in another response would come in handy then. – preinheimer May 18 '14 at 16:34

score 0 · Answer 2 · answered May 18 '14 at 16:32

0

OR syntax in PHP:

if($var == 'something' || $var == 'something else')
{
  //do something
}

For reference:

|| means OR

&& means AND

answered May 18 '14 at 16:32

psx

4,040
6
30
59

score 0 · Answer 3 · answered May 18 '14 at 16:32

For a more future-proof solution, consider in_array. I use it for as few as two options, if there's even the slightest chance there may be more added.

if( in_array($input, ["DeOnTRAY96@localhost", "somethingelse"]))

Once you get to four or more options, it's probably better to do something more like:

$whitelist = [
      "DeOnTRAY96@localhost"
    , "somethingelse"
    , "anotheroption"
    , "too many options to do inline!"
];
if( in_array($input, $whitelist))

PHP Syntax: "or" in "If" Statement

3 Answers3