if statement containing not in

Question

This if statement works...when I'm only looking for one string

    body = json.dumps(work['Body'])[2:-2]
    if len(something) >= 1 and 'SMILE' in body:
           print " i'm happy"

But this one does not when i'm looking for multiple strings....

    body = json.dumps(work['Body'])[2:-2]
    if len(something) >= 1 and 'SMILE' or 'LAUGH' or 'LOVE' or 'CHEER' in body:
           print " i'm still happy "

What gives? How can I have multiple string in the if condition to match against another string?

`or` isn't a conjunction in Python; it's a boolean operator. It doesn't do anywhere near the amount of stuff the English conjunction "or" does. — user2357112, May 19 '14 at 06:09

score 2 · Accepted Answer · edited May 19 '14 at 06:05

2

Assuming body is some string, you can do as follows using any:

# for example
body='SMILE_LAUGH_SOMESTRING_WHTATEVER'
if len(something) >= 1 and any(s in body for s in ('SMILE', 'LAUGH', 'LOVE', 'CHEER')):
     print("i'm still happy")

edited May 19 '14 at 06:05

Tim

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answered May 19 '14 at 06:04

Marcin

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what would be the opposite... so that i want to say "not in"... i want to have another if statement that says do xyz if those keywords are not in the string? – user3467359 May 19 '14 at 06:08
You could use [all](https://docs.python.org/2/library/functions.html#all) also. Or `not all(...)` or any combination depending what you want. – Marcin May 19 '14 at 06:12
@user3467359 `and not any(` would be the opposite – Tim May 19 '14 at 06:15

if statement containing not in

1 Answers1