Append PHP code into jQuery.

Question

I have a jquery function include html select and input, it shows form with selectable value name is olcu

<script type="text/javascript">
$(document).ready(function() {
    $("#add").click(function() {
        var intId = $("#buildyourform div").length + 1;
        var fieldWrapper = $("<div class=\"fieldwrapper\" id=\"field" + intId + "\"/>");
        var fMiktar = $("<input type=\"text\" class=\"miktar\" name=\"miktar[]\" size=\"6px\" />");
        var fOlcu = $("<select class=\"olcu\" name=\"olcu[]\"><option value=\"Adet\">Adet</option><option value=\"Metre\">Metre</option><option value=\"Gram\">Gram</option></select>");
        var fMalzeme = $("<input type=\"text\" name=\"malzeme[]\" class=\"malzeme\" id=\"aramayap\" />");
        var removeButton = $("<input type=\"button\" class=\"remove\" value=\"-\" />");
        removeButton.click(function() {
            $(this).parent().remove();
        });
        fieldWrapper.append(fMiktar);
        fieldWrapper.append(fOlcu);
        fieldWrapper.append(fMalzeme);
        fieldWrapper.append(removeButton);
        $("#buildyourform").append(fieldWrapper);
    });

});
</script>

I want to take values of olcu from database

And here is the database code

<script type="text/javascript">
    function showSelected(val){
        document.getElementById ('selectedResult').innerHTML = "" + val;
    }

</script>

<select name="olcu[]" onChange='showSelected(this.value)' class="olcu" id="olcu">Olcu Sec/option>

<?php

while($olculer=mysql_fetch_array($hangiolcu)){
echo "<option value='$olculer[olcu]'>$olculer[olcu]</option>";
}
?>
</select>

How can I append or replace that sql code into this jquery line

var fOlcu = $("<select class=\"olcu\" name=\"olcu[]\"><option value=\"Adet\">Adet</option><option value=\"Metre\">Metre</option><option value=\"Gram\">Gram</option></select>");

Why don't you use better jQuery selector for elements? *by giving `class` name or `ID` ?* — Ravi Dhoriya ツ, May 19 '14 at 07:06
this looks strange (mix od javascript and php code), why dont you get data with ajax? — Bojan Kovacevic, May 19 '14 at 07:08
Your *Database Code* is not database code. It simply prints options from your database query. What you actually want to achieve is very unclear. What is that jQuery line supposed to do? I think you might have a [XY Problem](http://mywiki.wooledge.org/XyProblem). — Andresch Serj, May 19 '14 at 07:14

score 2 · Answer 1 · answered May 19 '14 at 07:15

2

You can create Javascript/jQuery variable with PHP code like this:

var foo = '<?php //echo or return php value here; ?>';

answered May 19 '14 at 07:15

developer10

1,450
2
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31

Can you please combine code? – Seyhan May 19 '14 at 07:24

Append PHP code into jQuery.

1 Answers1