AND for java compiled pattern

Question

I'm pretty new to java regexp and trying to compile a Pattern that simplifies this:

String str1;
String str2;
String str3;
String str4;
String str;

if ((str.contains(str1) || str.contains(str3)) &&
        str.contains(str3) || str.contains(str)) {
    return true;
} else {
    return false;
}

I figured out I can do the OR with "|" but how do I compile the AND?

I want to be able to compile the pattern and check many strings with good performance.

EDIT:

I got this now :

private static boolean checkPatternOR() {

    String patternString = "foo"  ;

    Pattern pattern = Pattern.compile(patternString, Pattern.CASE_INSENSITIVE);

    Matcher matcher1 = pattern.matcher("foo bar");
    Matcher matcher2 = pattern.matcher("something else");


    System.out.println("does it match? " + (matcher1.lookingAt() && matcher2.lookingAt()));

    return true;

}

How would I merge matcher1 and matcher2 into one?

The expression always evaluates to true, since the right-most thing is "|| str.contains(str)". — Paul Hankin, May 20 '14 at 10:29

score 0 · Answer 1 · answered May 20 '14 at 10:30

0

// [] is how you match regex patterns by OR 
if(str.matches("[(*str1 here*)(*str2 here*)(*etc*)]")
    // best to separate AND into a separate regex
    && str.matches("regex here")) {
    // do whatever
}

If I've understood you correctly.

If not, then just encase your Java OR statements (||, ||, ||) in brackets:

if((str.contains(str1) || str.contains(str2) && (str.contains(str3)) {
    // do whatever
}

answered May 20 '14 at 10:30

Gorbles

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Downvotes with no reason aren't appreciated, either. – Gorbles May 20 '14 at 11:19

AND for java compiled pattern

1 Answers1