How can I achieve converting a list to 2d list this using itertools or collections with high performance

Question

By simply technique i can think of, I am converting a list to 2d list, However is it possible to achievie this with higher performance either by itertools or collections?

n = 2
lst = ['a', 'b', 'c', 2, 'e']
for i in  range(0, len(lst), n):
    print lst[i:i+n]

Expected output:

[['a', 'b'], ['c', 2], ['e']]

@MartijnPieters : I am using a 2d list for passing the list of image paths to `QListview` however no intentions for what you have voted to close. — Ciasto piekarz, May 20 '14 at 16:01

score 0 · Accepted Answer · answered May 20 '14 at 16:07

0

>>> thing = [lst[i:i+n] for i in range(0,len(lst),n)]
>>> thing
[['a', 'b'], ['c', 2], ['e']]

Using a list comprehension

answered May 20 '14 at 16:07

kylieCatt

10,672
5
43
51

How can I achieve converting a list to 2d list this using itertools or collections with high performance

1 Answers1