PHP how to check if image url is false

Question

How can I check if a url directs to an image file, and http://website.com/images-stories/gallery/image-name.jpg

and if there is no file in the location, default to another url (for a default file).

I was using file_exists but realize that checks a path not a url.

<?PHP
    while ($data = mysqli_fetch_assoc($result)):

    $smaller_img = $data['smaller_img'];


    $url = $smaller_img;
    $ch = curl_init($url);
    curl_setopt($ch, CURLOPT_HEADER, true);    // we want headers
    curl_setopt($ch, CURLOPT_NOBODY, true);    // we don't need body
    curl_setopt($ch, CURLOPT_RETURNTRANSFER,1);
    curl_setopt($ch, CURLOPT_TIMEOUT,10);
    $output = curl_exec($ch);
    $httpcode = curl_getinfo($ch, CURLINFO_HTTP_CODE);
    curl_close($ch);

if ($httpcode=200) 
{
$smaller_imgf=$url;
} else {
$smaller_imgf='../images/submit_icon.png';
}  
    ?>

<img src="<?php echo $smaller_imgf; ?>

You should use `cURL` in addition to checking returning header — revo, May 21 '14 at 15:56
Looks a lot like: http://stackoverflow.com/questions/1722613/check-if-a-remote-page-exists-using-php — Stefan, May 21 '14 at 15:56
`get_headers($url, 1)` with `stream_context` set to only `HEAD` or - `curl` with fetch headers only — Daniel W., May 21 '14 at 15:58
you can check it with exif_imagetype(); function. if (exif_imagetype('image.gif') != IMAGETYPE_GIF) { echo 'This is not gif.'; } [Click Here For More Information][1] [1]: http://www.php.net/manual/tr/function.exif-imagetype.php — Burhan Çetin, May 21 '14 at 16:01

score 2 · Accepted Answer · edited May 23 '17 at 12:10

2

You can look with curl for status code 200

https://stackoverflow.com/a/11797723/2441442

If 200, you can check for image with getimagesize

http://www.php.net/manual/de/function.getimagesize.php

edited May 23 '17 at 12:10

Community

1
1

answered May 21 '14 at 15:56

Christian Gollhardt

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Thank you @christian golhardt. I posted my current script and I'm having an issue, I have a feeling I'm doing something incorrectly when defining $httpcode – rhill45 May 21 '14 at 16:36
1

`($httpcode=200)` should be `($httpcode==200)` ;) – Christian Gollhardt May 21 '14 at 16:38
1

@buzrw I recommend you a good IDE such as `PHP Storm`. It will warn you, if you make a mistake and have unreachable code :) – Christian Gollhardt May 21 '14 at 18:28

PHP how to check if image url is false

1 Answers1