JavaScript Regular expression to test input string is between 1-10 chars with no whitespace

Question

I'm trying to validate user input to return valid if and only if a input string is between 1-10 chars in length and contains no whitespace or non a-z chars.

I'm using this regular expression

var re = /(\S[a-z]){1,10}/;

but this returns true when numbers are input. And if white space if input e.g

1 returns valid.
a a returns valid.

I want to restrict the input to only between l-10(amount) of letters(lowercase) What I have so far;

http://codepen.io/anon/pen/ILKkz

possible duplicate of [Regex for numbers only](http://stackoverflow.com/questions/273141/regex-for-numbers-only) — devnull, May 23 '14 at 16:25
It is unclear what you want to match. Only digit/number characters? Only a-z characters? Give examples of what you want to be valid and invalid. — Cory, May 23 '14 at 18:06
edited. So "a" is valid, "a1" is invalid, "abcdefjklj" valid, "abcdefjkljz" invalid. — user3669639, May 23 '14 at 19:39

score 1 · Accepted Answer · answered May 23 '14 at 19:40

Use the following expression:

var re = /^[a-z]{1,10}$/;

This will anchor your match to the beginning (^) and end ($) of your string. Also, if you just want to allow lowercase letters, all you need is the [a-z] and nothing like \S. However, if you want to allow anything but whitespace you would use ^\S{1,10}$.

JavaScript Regular expression to test input string is between 1-10 chars with no whitespace

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