Regex to capture src in php

Question

I'd like to extract the img src and using preg_match_all I have this:

$tag = '<img src="path/to/image.png" />';
preg_match_all('/(width|height|src)=("[^"]*")/i',$tag, $img[$tag]);

which returns:

Array
(
[<img src="path/to/image.png" />] => Array
    (
        [0] => Array
            (
                [0] => src="path/to/image.png"
            )

        [1] => Array
            (
                [0] => src
            )

        [2] => Array
            (
                [0] => "path/to/image.png"
            )

    )

)

How can I write the regex to return a similar result regardless of double or single quotes used in tag? I can write:

$tag = "<img src='path/to/image.png' />";
preg_match_all('/(width|height|src)=(\'[^\']*\')/i',$tag, $img[$tag]);

Which works, but I'm not familiar enough with regex to write one expression to handle either. I did try:

preg_match_all('/(width|height|src)=((\'[^\']*\')|("[^"]*"))/i',$tag, $img[$tag]);

But this seems to return extra matches in the array which I don't want.

http://stackoverflow.com/questions/1732348/regex-match-open-tags-except-xhtml-self-contained-tags — mleko, May 23 '14 at 17:39
yes, a timeless question and timeless answer. quite an enjoyable read — But those new buttons though.., May 23 '14 at 18:03

score 3 · Accepted Answer · answered May 23 '14 at 17:39

3

You can use this:

(width|height|src)=("[^"]*"|'[^']*')

I've basically used an alternation to either match "fds" or 'fds'.

answered May 23 '14 at 17:39

Farhad Alizadeh Noori

2,276
17
22

Thanks! I know various permutations of this have been asked but mine it not so much about extracting the img as it is about regex syntax for the alternation as you demonstrated. That is exactly what I was going for but still learning regex. – But those new buttons though.. May 23 '14 at 18:05

Regex to capture src in php

1 Answers1