Default argument to Python attribute that is a function

Question

I was wondering if it is possible in Python to specify a default argument to a function attribute in Python (I know this is not the right terminology so here is an example):

def foo(x, y): 
    return x + y

my_foo = foo(y=50)

my_foo(25) #returns 75

Does this sound possible?

See http://stackoverflow.com/questions/3188048/how-to-bind-arguments-to-given-values-in-python-functions. — Waleed Khan, May 30 '14 at 16:39
To have a default argument, use def foo(x=0, y=0): [...] directly — abrunet, May 30 '14 at 16:40

score 2 · Accepted Answer · edited May 23 '17 at 12:20

2

from functools import partial
def foo(x, y): return x + y
my_foo = partial(foo, y=50)
my_foo(100)
Out[433]: 150

But you should know about this.

edited May 23 '17 at 12:20

Community

1
1

answered May 30 '14 at 16:40

newtover

31,286
11
84
89

score 1 · Answer 2 · answered May 30 '14 at 16:40

1

You'd do it in the function definition:

def foo(x, y=50):
    return x+y

if y isn't specified 50 is the default value:

print foo(25) # 25 is the value for x, y gets the default 50

answered May 30 '14 at 16:40

Ben

2,065
1
13
19

Your answer is only valid only because it doesn't matter which argument gets the default value for this particular sample function -- a fairly unique situation -- so isn't something generally applicable. – martineau Dec 28 '14 at 17:38

Default argument to Python attribute that is a function

2 Answers2