Get a variable out of a try

Question

I have a problem using a variable surrounded with a try : Here's the beginning of my method :

public static word[] countWords(String text) {
    try {
            text = Preprocesseur.preprocess(text);
    } 
    catch (IOException e) {
            System.out.println("Error méthod countWords");
            e.printStackTrace();
    }

Actually i need to use the String text (preprocessed) several line after, but java doesn't affect the value Preprocesseur.preprocess(text) to the whole method --> it stays in the try/catch block

I was wondering : how to call my method Preprocesseur.preprocess and affect its return String to the whole countWords method ? Because a try/catch block is required (or throws declaration which leads to the same result)

Very quick thought: public class MyPreprocesseurException extends IOException { public String getTextInProgress() {} } Does that make sense? — Julius Musseau, Jun 02 '14 at 18:35
Tis somewhat of an anti-pattern to reassign method arguments... — Boris the Spider, Jun 02 '14 at 18:40

score 0 · Accepted Answer · answered Jun 02 '14 at 18:35

0

You can simply switch from catching exceptions to throwing them higher form your method and deal with your problems later, like this:

public static word[] countWords(String text) throws IOException {
        text = Preprocesseur.preprocess(text);
}

answered Jun 02 '14 at 18:35

TheMP

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Get a variable out of a try

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