It's best to think of let
in terms of Static Single Assignment (SSA) -- every SSA variable is assigned to exactly once. In functional languages like lisp you don't (normally) use an assignment operator -- names are bound to a value exactly once. For example, the names y
and z
below are bound to a value exactly once (per invocation):
func pow(x: Float, n : Int) -> Float {
if n == 0 {return 1}
if n == 1 {return x}
let y = pow(x, n/2)
let z = y*y
if n & 1 == 0 {
return z
}
return z*x
}
This lends itself to more correct code since it enforces invariance and is side-effect free.
Here is how an imperative-style programmer might compute the first 6 powers of 5:
var powersOfFive = Int[]()
for n in [1, 2, 3, 4, 5, 6] {
var n2 = n*n
powersOfFive += n2*n2*n
}
Obviously n2
is is a loop invariant so we could use let
instead:
var powersOfFive = Int[]()
for n in [1, 2, 3, 4, 5, 6] {
let n2 = n*n
powersOfFive += n2*n2*n
}
But a truly functional programmer would avoid all the side-effects and mutations:
let powersOfFive = [1, 2, 3, 4, 5, 6].map(
{(num: Int) -> Int in
let num2 = num*num
return num2*num2*num})