trying to obtain a first name in the path after first back slash

Question

I want to display the first folder name from the path. /mnt/sdcard/Videos/lk.jpeg, I want to display mnt string. in java

/mnt/sdcard/Videos/lk.jpeg--> **mnt**

score 2 · Answer 1 · answered Jun 03 '14 at 11:26

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You can split on / and use [1] element from result array.

answered Jun 03 '14 at 11:26

Pshemo

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An example of `split` is here http://stackoverflow.com/questions/3481828/how-to-split-a-string-in-java – Illidanek Jun 03 '14 at 11:27
@downvoter Any problems with this approach? – Pshemo Jun 03 '14 at 11:28
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What is happening here?. @Pshemo is correct.. arr[0] will contain an empty String.. arr[1] will have the actual value.. – TheLostMind Jun 03 '14 at 11:30
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@OlegS. "*[1] element from result array*" isn't `[index]` + `array` clear enough? Should I really make it more clear by writing `array[index]`? – Pshemo Jun 03 '14 at 11:33
Ok, fair enough, my bad -- voted back up – Oleg Sklyar Jun 03 '14 at 11:35

score 2 · Answer 2 · answered Jun 03 '14 at 11:31

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You can either use regular expressions or you can use String.split(). Note that the split() result should be checked for live usage (e.g. if it has at least two elements).

String desired = "/mnt/sdcard/foo".split("/")[1];

answered Jun 03 '14 at 11:31

Danstahr

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score 1 · Accepted Answer · answered Jun 03 '14 at 11:32

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String str = "/mnt/sdcard/Videos/lk.jpeg";
System.out.println(str.split("/")[1]);

Try this out. This is a poor question. But maybe the asker can be a newbie.

answered Jun 03 '14 at 11:32

Dinal

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Are you using the exact same code I pasted here. There would be five elements in the array...Then how will it throw ArrayIndexOutOfBoundsException. If you are using some other string then enclose the statements with this condition. if(str.split("/").length > 1) – Dinal Jun 03 '14 at 11:42

trying to obtain a first name in the path after first back slash

3 Answers3