Sorting a dict in python

Question

I have a dict as in below:

saving = {0: (1, 2, 9.0), 1: (1, 3, 603.0), 2: (1, 4, 396.0), 3: (1, 5, 9.0), 4: (2, 3,     206.0)}

I want to sort descending this dict order by the third value.
I tried sorted and sort() but I couldn't sort the dict. I don't know much about the usage sort and sorted functions. Can you help me ? Thanks.

Dicts are inherently orderless... – Fredrik Pihl Jun 03 '14 at 14:00 — Fredrik Pihl, Jun 03 '14 at 14:00

minder · Accepted Answer · 2014-06-03T14:56:27.403

0

Probably OrderedDict is what you're looking for. It behaves like a dictionary, but its keys can be sorted. Standard python dictionaries are inherently unordered.

In your case this should work:

d = OrderedDict(sorted(saving.items(), key=lambda t: t[1][2]))

edited Jun 03 '14 at 14:56

answered Jun 03 '14 at 14:02

minder

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I used this code below, but nothing happened:OrderedDict(sorted(saving.items(), key=lambda t: t[2])) – user3703206 Jun 03 '14 at 14:10
I used your code and it threw an exception. You used wrong sorting key since sorted() outputs a tuple. – minder Jun 03 '14 at 14:57

Sorting a dict in python

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