Hidden default constructor

Question

Why does the code below compile?

class Test
{
    public:
        Test(int i) {}
    private:
        Test();
};

int main()
{
    // OK - uses Test(int i)
    Test test(5);

    // Error - Test() is private
    // Test test2;

   // Why does this compile? Test() is private!
   Test test3();
}

I would think that the last instanciation would fail to compile since the no-param constructor is private?

`Test test3();` is treated as a function declaration, not construction of object. — Rakib, Jun 05 '14 at 08:43

score 2 · Accepted Answer · answered Jun 05 '14 at 08:43

2

Test test3(); is a function declaration. It declares a function named test3 of type int(). It's OK to declare things in C++, even if they're never defined (since you're not trying to actually call it).

answered Jun 05 '14 at 08:43

Kerrek SB

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Thanks! That makes sence. – Q-bertsuit Jun 05 '14 at 08:59

Hidden default constructor

1 Answers1