Can anyone help me out, I am not getting how gcc is compiling the below statement and printing its output.:-
printf("%d",7["sunderban"]);
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Gcc is taking base address of "sunderban" adding 7 to it and printing the decimal equivalent of data at that location,which is for 'a' is 97. – Vagish Jun 06 '14 at 12:10
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2You are asking about the output of that statement, without stating what this output is, and why it's unexpected to you. Please improve your question. – moooeeeep Jun 06 '14 at 12:12
1 Answers
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C allows to access array's elements in two ways (see Accessing arrays by index[array] in C and C++ and the answers) :
int v[5];
// 1)
v[2] = 33;
// 2)
2[v] = 44;
So, what happens in your case is that you access the 8th element of the string, and it is interpret as int by the printf.
