Prevent Python from showing entered input

Question

In Python when I change the value of a variable through raw_input in the terminal it would write a new line stating its new value. I wanted to know if there is a way to avoid that because straight after user's input there is a print function which uses the value received before. In the end the user will get both values: original and modified while for the purpose of my program he only has to see the modified.

I use IDLE to write my scripts and then execute them in terminal.

Update

A simple example would be the following. The input is string "Hello" and the output should be "Me: Hello". There should be no "Hello" before the final result.

a = raw_input()
print ("Me: " + a)

And the output should be just

Me: Hello

rather than

Hello
Me: Hello

Could you post the output you are getting and the output you are wanting? — Dylan, Jun 06 '14 at 17:23
Show the actual code you're referring to - it isn't clear exactly what the issue is. — EML, Jun 06 '14 at 18:22

yedpodtrzitko · Accepted Answer · 2014-06-06T22:04:24.980

1

if you want user to see the input, just mute sys.stdout (it's a bit hack tho):

>>> from StringIO import StringIO
>>> import sys
>>> orig_out = sys.stdout
>>> print 'give me input: ',
give me input: 
>>> sys.stdout = StringIO()
>>> a = raw_input('')
string I type
>>> sys.stdout = orig_out
>>> a
>>> 'string I type'

...and if you put this into a function then it's exactly what you want!

a.py

....

def foo():
    orig_out = sys.stdout
    print 'give me input: ',
    sys.stdout = StringIO()
    a = raw_input()
    sys.stdout = orig_out

if __name__ == '__main__':
    foo()

running:

yed@rublan $ ~ python a.py

give me input: something I type!!!!!

yed@rublan $ ~

edited Jun 06 '14 at 22:04

answered Jun 06 '14 at 17:40

yedpodtrzitko

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I already tried using this function but the problem is that the user can't see text he is typing before submission. – KopakaTon Jun 06 '14 at 17:50
what about this hack with `stdout`? .) – yedpodtrzitko Jun 06 '14 at 18:04
I have added an example – KopakaTon Jun 06 '14 at 19:47
1

so what?! have you tried the code I put into my answer earlier? It works exactly as you want – yedpodtrzitko Jun 06 '14 at 20:27

score 1 · Answer 2 · answered Sep 08 '18 at 15:43

I know this is a late answer, but here is a Python 2+3 solution (with a small improvement):

In prompt_demo.py:

# coding: utf-8
from __future__ import absolute_import
from __future__ import print_function

import io
import sys

import six.moves


def prompt(msg):
    print(msg, end=u'')
    orig_out = sys.stdout
    try:
        sys.stdout = io.StringIO()
        return six.moves.input(msg)
    finally:
        sys.stdout = orig_out


if __name__ == '__main__':
    text = prompt(u"Give me input: ")
    print(u"Do you mean '{0}'?".format(text))

This solution uses io.StringIO, which is the Python 2+3 compatible.
It also uses the six library to backport the raw_input function (which is renamed input in Python 3).
The try ... finally solution is better in case of exception during the input: it restores the original value of sys.stdout.

I also want to point the nice solution available in the Click library. Here is a demo:

import click

if __name__ == '__main__':
    text = click.prompt(u"Give me input: ", prompt_suffix='')
    click.echo(u"Do you mean '{0}'?".format(text))

See the documentation about click.prompt.

score -2 · Answer 3 · answered Sep 08 '18 at 15:00

You don't have to do difficult things like that, the answser is really simple:

chat_respond="you say: "+input("Write here to respond: ")
#i will suppose that you want to write hello
#That will display:
Write here to respond: hello

Because automaticaly the input is printed, it will show the string of the variable but you add something before the input so it will print that plus the input

you say: hello

You don't need to use difficult librairies or modify a module, just to add to the variable before you stock the input, you can also do that:

chat_respond="you say: "
chat_respond+=input("Write here to respond: ")

It will do the same Bye!

Prevent Python from showing entered input

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