find all links with regular expression in python

Question

I have a text full of link address with style

href=\'http://address.com\'

I use re.findall('"((http)s?://.*?)"', srcCode) in Python 3.4 to extract all links, but doesn't work. How can I fix it?

score 1 · Answer 1 · answered Jun 08 '14 at 08:12

1

swap the quotes

re.findall("'((http)s?://.*?)'", srcCode)

answered Jun 08 '14 at 08:12

griffon vulture

1

Should be `(?:http)` if the OP doesn't want to capture that separately – jonrsharpe Jun 08 '14 at 08:13
i tested this, but doesn't work :(. this re when works that my test has `href='http://address.com'` but my text has link with style `href=\'http://address.com\'`. – user2517728 Jun 08 '14 at 09:39
when i run, return epmty list []. – user2517728 Jun 08 '14 at 09:47
re should be `re.findall("'((http)s?://.*?).\'", srcCode)` – user2517728 Jun 08 '14 at 09:59
there is not any difference between `"'((http)s?://.*?).\'"` and `"'((http)s?://.*?).'"` the both have same result in console – griffon vulture Jun 08 '14 at 10:00

1 Answers1