Contrary to the other answers, I assert that in principle the short answer is YES. This is likely not supported officially in any way, but it appears to work. At the end of this answer I present a demo.
On Linux-x86_64, a 32 bit (and X32 too, according to GDB sources) process gets CS
register equal to 0x23
— a selector of 32-bit ring 3 code segment defined in GDT (its base is 0
). And 64 bit processes get another selector: 0x33
— a selector of long mode (i.e. 64 bit) ring 3 code segment (bases for ES
, CS
, SS
, DS
are treated unconditionally as zeros in 64 bit mode). Thus if we do far jump, far call or something similar with target segment selector of 0x33
, we'll load the corresponding descriptor to the shadow part of CS
and will end up in a 64 bit segment.
The demo at the bottom of this answer uses jmp far
instruction to jump to 64 bit code. Note that I've chosen a special constant to load into rax
, so that for 32 bit code that instruction looks like
dec eax
mov eax, 0xfafafafa
ud2
cli ; these two are unnecessary, but leaving them here for fun :)
hlt
This must fail if we execute it having 32 bit descriptor in CS shadow part (will raise SIGILL on ud2
instruction).
Now here's the demo (compile it with fasm).
format ELF executable
segment readable executable
SYS_EXIT_32BIT=1
SYS_EXIT_64BIT=60
SYS_WRITE=4
STDERR=2
entry $
mov ax,cs
cmp ax,0x23 ; 32 bit process on 64 bit kernel has this selector in CS
jne kernelIs32Bit
jmp 0x33:start64 ; switch to 64-bit segment
start64:
use64
mov rax, qword 0xf4fa0b0ffafafafa ; would crash inside this if executed as 32 bit code
xor rdi,rdi
mov eax, SYS_EXIT_64BIT
syscall
ud2
use32
kernelIs32Bit:
mov edx, msgLen
mov ecx, msg
mov ebx, STDERR
mov eax, SYS_WRITE
int 0x80
dec ebx
mov eax, SYS_EXIT_32BIT
int 0x80
msg:
db "Kernel appears to be 32 bit, can't jump to long mode segment",10
msgLen = $-msg