Convert IEnumerable> to IEnumerable

Question

What is the best way to convert IEnumerable<IGrouping<T,K>> to IEnumerable<K> ?

It seems this way will work:

myEnumerable = myEnumerableOfGroups
    .Select( group => group.AsEnumerable)
    .Aggregate((enumA, enumB) => enumA.Concat(enumB));

is there a more efficient way to do it ?

That depends on what you want to accomplish. Are you just wanting to iterate all of the K objects in each grouping sequentially, that is undo the grouping? — cdhowie, Jun 09 '14 at 14:55
Watch out @cdhowie, if you stop to ask questions you'll miss the rep train. Three answers in the same second. — Rawling, Jun 09 '14 at 14:57
@Rawling I'd rather have a clearly documented question than a few silly rep points. — cdhowie, Jun 09 '14 at 14:58
Try to answer a question containing `IEnumerable` in the topic, Andddd its 10 answer in the same second — Yuval Itzchakov, Jun 09 '14 at 14:59
Yes, the purpose was to undo the grouping, and it seems SelectMany is exactly that — MichaelB, Jun 09 '14 at 15:05

score 1 · Accepted Answer · answered Jun 09 '14 at 14:55

1

This should do it:

myEnumerable = myEnumerableOfGroups.SelectMany(group => group);

The MSDN page for this overload of SelectMany is here.

answered Jun 09 '14 at 14:55

Ani

Wow, that was fast :), Thanks – MichaelB Jun 09 '14 at 15:01
1

@MichaelB It's a shame that the fastest reaction to such a question is "rep!" not "maybe it's a duplicate". – Rawling Jun 09 '14 at 15:02
2

@MichaelB That tells you just how little research you did before asking your question, not how skilled of a poster any of the people who answered the question were. – Servy Jun 09 '14 at 15:02

1 Answers1