C++ access to function argument private variable

Question

 class Container{



private:
    int num_;

public:

    Container(): num_(1)
    {};

    void add(Container other){
        num_+=other.num_;
    }

    int get_num(){
        return num_;
    }

    void set_num(int n){
        num_=n;
    }

};

In the above example other.num_ is accessible... Why? Shouldn`t it be unaccessible due to the private modifier?

Because in C++ encapsulation is per class, not per object. It means that any object of type Container can access private members, it doesn't matter if they're in a different object. — Adriano Repetti, Jun 09 '14 at 16:25

deeiip · Accepted Answer · 2014-06-09T16:33:12.460

A class can always access it's own member, whatever access modifier a member variable it has.
private: only the class can access
protected: only derived classes can access
public: everyone can access
If you write:

class Container{
private:
    int num_;
}

Every object can access private members of any other object of same class because in c++ access modifier is for a class not for each object of that class.

C++ access to function argument private variable

1 Answers1