CGSize sizeWithAttributes in Swift

Question

In objective-C I was able to use:

    CGSize stringsize =
     [strLocalTelefone sizeWithAttributes:@{NSFontAttributeName:[UIFont systemFontOfSize:14.0f]}];

But in Swift Language I didn't found any solution for this situation.

Any Help?

I can't find a solution to get the size of text in CGSize object... — Naldo Lopes, Jun 10 '14 at 13:05
@NaldoLopes, just an FYI, typically questions are not re-edited to include the solutions. Questions and answers are designed to be separate. By checking an answer it tells people what the solution you used was. — Firo, Jun 10 '14 at 13:25

score 160 · Answer 1 · edited Jun 20 '20 at 09:12

160

what I did is something like this:

swift 5.x

let myString = "Some text is just here..."
let size: CGSize = myString.size(withAttributes: [.font: UIFont.systemFont(ofSize: 14)])

swift 4.x

let myString = "Some text is just here..."
let size: CGSize = myString.size(withAttributes: [NSAttributedStringKey.font: UIFont.systemFont(ofSize: 14)])

swift 3

var originalString: String = "Some text is just here..."
let myString: NSString = originalString as NSString
let size: CGSize = myString.size(attributes: [NSFontAttributeName: UIFont.systemFont(ofSize: 14.0)])

swift 2.x

var originalString: String = "Some text is just here..."
let myString: NSString = originalString as NSString
let size: CGSize = myString.sizeWithAttributes([NSFontAttributeName: UIFont.systemFontOfSize(14.0)])

edited Jun 20 '20 at 09:12

Community

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answered Jun 10 '14 at 13:21

holex

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@holex What if I am using Custom font? – Developer Nov 12 '14 at 10:49
@Developer, obviously you need to use the custom font instead of the system font. – holex Nov 12 '14 at 10:51
@holex I am new to Swift. I meant how will I write line of code for that with size? – Developer Nov 12 '14 at 10:54
@Developer, the `UIFont` class reference can give you more information how you can init a custom font, I would say to take a closer look on the `+fontWithName:size:` method. (here is the complete reference: https://developer.apple.com/Library/ios/documentation/UIKit/Reference/UIFont_Class/) – holex Nov 12 '14 at 10:58
@holex Yes I saw that already but I am not able to call this function in the following line.---- let size: CGSize = myString.sizeWithAttributes([NSFontAttributeName: UIFont.systemFontOfSize(14.0)])----. How Helvetica with size 15 can be set in the attribute? – Developer Nov 12 '14 at 11:07
@holex Any opinion on this? – Developer Nov 12 '14 at 11:28
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@Developer, the line `let size: CGSize = myString.sizeWithAttributes([NSFontAttributeName: UIFont(name: "Helvetica", size: 15.0)!])` works for me with no problem, I'm not sure where you have been stuck at. – holex Nov 12 '14 at 11:32
Let us [continue this discussion in chat](http://chat.stackoverflow.com/rooms/64783/discussion-between-developer-and-holex). – Developer Nov 12 '14 at 11:45
How can i get button text? – Toseef Khilji Nov 13 '14 at 07:21
@Virussmca, have you taken a look on the `UIButton` class reference? you would have found a method, called `–titleForState:`, that gives the text of your instance. (_source_: https://developer.apple.com/library/ios/documentation/uikit/reference/uibutton_class/index.html) – holex Nov 13 '14 at 09:05
@holex: yes i can able to get button text but it gives errors, can you just edit your answer for getting text size from button ? – Toseef Khilji Nov 13 '14 at 11:13
@Virussmca, unfortunately I can't update my answer with that, the OP has no such request of any buttons or its any sizes. If you have a new issue, please raise a new post about it and the community will probably answer to you. – holex Nov 13 '14 at 11:56
I have a unicode string so how can i get the size of that string using sizeWithAttributes? – Navneet Sharma Apr 16 '18 at 15:09
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@NavneetSharma, `String` in Swift fully supports unicode characters, so it should be no difference at all. – holex Apr 17 '18 at 07:51
no need for the NSAttributedStringKey.font it can be written as .font it is inferred to be NSAttributedStringKey ==> size(withAttributes: [.font : UIFont(...)]) – J. V. Sep 10 '18 at 04:37

score 8 · Answer 2 · edited May 23 '17 at 11:54

8

Just use explicit casting:

var stringsize = (strLocalTelefone as NSString).sizeWithAtt...

~~Otherwise you can bridge it too:~~
Bridging is no longer supported in later versions of Swift.

var strLocalTelefone = "some string"
var stringsize = strLocalTelefone.bridgeToObjectiveC().sizeWithAttributes([NSFontAttributeName:UIFont.systemFontOfSize(14.0)])

This answer is worth at least looking at, as it highlights potential differences between the two approaches.

edited May 23 '17 at 11:54

Community

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answered Jun 10 '14 at 13:07

Firo

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The bridge is unnecessary. Swift `String`s seamlessly bridge to `NSString`. – Bill Jun 10 '14 at 14:56
@Bill true, but bridging allows you to call `sizeWithAttributes` directly, rather than creating a new constant with a name (as shown in the accepted answer). It is less code and basically does the same thing (as bridging gives you an `NSString`). So I would argue creating a new named constant is unnecessary. – Firo Jun 10 '14 at 14:58
how can i set button titlelabel text in place of "some string"? – Toseef Khilji Nov 13 '14 at 07:21
You can just access the button's `titleLabel`: `self.myButton.titleLabel.text`. Is that what you are looking for – Firo Nov 13 '14 at 15:05

score 7 · Accepted Answer · answered Sep 17 '18 at 04:52

7

Just one line solution:

yourLabel.intrinsicContentSize.width for Objective-C / Swift

This will work even your label text have custom text spacing.

answered Sep 17 '18 at 04:52

Alok

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score 2 · Answer 4 · answered Mar 26 '15 at 09:49

You can also use this piece of code, it's easier and you don't have to create new variable just to get NSString object:

var stringToCalculateSize:String = "My text"
var stringSize:CGSize = (stringToCalculateSize as NSString).sizeWithAttributes([NSFontAttributeName: UIFont.systemFontOfSize(14.0)])

score 0 · Answer 5 · answered Apr 21 '15 at 06:26

0

On xCode 6.3, this is what you need to do now:

    let font:AnyObject = UIFont(name: "Helvetica Neue", size: 14.0) as! AnyObject
    let name:NSObject = NSFontAttributeName as NSObject
    let dict = [name:font]
    let textSize: CGSize = text.sizeWithAttributes(dict)

answered Apr 21 '15 at 06:26

user2962499

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Why are you doing all that weird casting? Why not just do `let dict = [NSFontAttributeName:UIFont(name: "Helvetica Neue", size: 14.0)!]` – Aaron Brager Apr 21 '15 at 06:39

score -3 · Answer 6 · answered Oct 19 '16 at 05:31

-3

On xCode 8.0, this is what you need to do now: let charSize = string.size(attributes: [NSFontAttributeName: UIFont.systemFont(ofSize: 20)])

answered Oct 19 '16 at 05:31

zhang dou

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Swift String type doesn't have this function. This is only for NSString. – Mihai Georgescu Mar 15 '17 at 07:32

CGSize sizeWithAttributes in Swift

6 Answers6

swift 5.x

swift 4.x

swift 3

swift 2.x

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