6

I have the following JSON object:

{
"response": {
    "status": 200
},
"messages": [
    {
        "message": {
            "user": "value"
            "pass": "value",
            "url": "value"
         }
 ]
    }

}

I am using JSON-Framework (also tried JSON Touch) to parse through this and create a dictionary. I want to access the "message" block and pull out the "user", "pass" and "url" values.

In Obj-C I have the following code:

// Create new SBJSON parser object
SBJSON *parser = [[SBJSON alloc] init];

// Prepare URL request to download statuses from Twitter
NSURLRequest *request = [NSURLRequest requestWithURL:[NSURL URLWithString:myURL]]; 

// Perform request and get JSON back as a NSData object
NSData *response = [NSURLConnection sendSynchronousRequest:request returningResponse:nil error:nil];

// Get JSON as a NSString from NSData response
NSString *json_string = [[NSString alloc] initWithData:response encoding:NSUTF8StringEncoding];

//Print contents of json-string
NSArray *statuses = [parser objectWithString:json_string error:nil];
NSLog(@"Array Contents: %@", [statuses valueForKey:@"messages"]);
NSLog(@"Array Count: %d", [statuses count]);


NSDictionary *results = [json_string JSONValue];
NSArray *tweets = [[results objectForKey:@"messages"] objectForKey:@"message"];

for (NSDictionary *tweet in tweets)
{
    NSString *url = [tweet objectForKey:@"url"];
    NSLog(@"url is: %@",url);
}

I can pull out "messages" and see all of the "message" blocks, but I am unable to parse deeper and pull out the "user", "pass", and "url".

Sheehan Alam
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  • The json string is malformed, the way you have written it here. The messages array has two open curly braces, and only one closing. – Felixyz Mar 10 '10 at 09:05

3 Answers3

9

Solved:

NSArray *tweets = [[results objectForKey:@"messages"] valueForKey:@"message"];
Sheehan Alam
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6
Array({

  0=>Dictionary({

      response =  Array({

        0=>Dictionary(Status = 200)

      })

    }),

  1=>Dictionary({

      messages = Array({

        0=> Dictionary({

          message = Array({

            0=>Dictionary({

              user = value,

              pass=value,

                 url=value

            })

          })

        })

      })

  })

})

So, to access dictionary for user, pass, url,

nsarray *arr = jsonmainarray;


arr = [[[jsonmainarray objectAtIndex: 1] objectforkey:@"messages"] objectatindex: 0];



nsdictionary *dict = [arr objectatindex: 0];

arr = [dict objectforkey:@"message"];

dict = [arr objectatindex: 0]; // Dictionary with user, pass, url
Brad Larson
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Paresh Thakor
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2

there is an easier way (in my opinion) to do JSON parsing :)

- (void)loadJSONData:(NSString *)u{
    NSURL *url = [NSURL URLWithString:[NSString stringWithFormat:@"http://expandurl.appspot.com/expand?url=%@", u]];
    NSData *rawJsonData = [NSData dataWithContentsOfURL:url];

    CJSONDeserializer *parser = [CJSONDeserializer new];
    NSError *error;
    NSDictionary *jsonDictionary = [parser deserializeAsDictionary:rawJsonData error:&error];

    [parser release];

    NSArray *array = [jsonDictionary objectForKey:@"urls"]; 
}

All you have to do is to use JSON touch... like Sheehan Alam mention.

Say that you got this line of JSON data:

{ "end_url" = "http://www.youtube.com"; redirects = 0; "start_url" = "http://www.youtube.com"; status = OK; urls = ( "http://www.youtube.com" ); }

then in your JSONDictonary the data can be accessed by doing:

[jsonDictionary objectForKey:@"urls"]; //This will return an Array since URLS is a array
[jsondictionary objectForKey:@"en_url"]; //this will return an NSString since end_url is a string

Hope this help people as much as it helped me =)

sincerely yours Kristian