Casting CGFloat to Float in Swift

Question

I need to store a value as a Float, but the source data is a CGFloat:

let myFloat : Float = myRect.origin.x

but this results in the compiler error: 'NSNumber' is not of subtype 'Float'

So if I explicitly cast it like this:

let myFloat : Float = myRect.origin.x as Float

but this in turn results in the compiler error: 'Cannot convert the expression's type 'Float' to 'Float''

What's the correct way to do this and satisfy the compiler please?

Be aware that on 64-bit systems, casting CGFloat to Float loses precision – CGFloat is 64 bits on 64-bit systems and 32 bits on 32-bit system, Float is always 32 bits. To avoid this, you could use Double instead of Float. — Lukas, Jun 10 '14 at 17:52
possible duplicate of [swift : Confusion due to no implicit conversion of CGFloat](http://stackoverflow.com/questions/24118134/swift-confusion-due-to-no-implicit-conversion-of-cgfloat) — Sulthan, Jun 10 '14 at 17:59
if you drill down on a CGFloat in Xcode and see where it is defined you will see that it is typedef'd as a float on 32 bit architecture and a double on 64 bit architecture. — jcpennypincher, Nov 24 '14 at 18:50

score 198 · Accepted Answer · edited May 07 '15 at 02:50

198

You can use the Float() initializer:

let cgFloat: CGFloat = 3.14159
let someFloat = Float(cgFloat)

edited May 07 '15 at 02:50

Jojodmo

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answered Jun 10 '14 at 17:47

Erik

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17

using "float" as variable name is somewhat confusing, perhaps change is to something like "swFloat"? – Fermat's Little Student Jul 24 '14 at 14:40
2

" 'float' is somewhat confusing". Seriously? – AlvinfromDiaspar Sep 16 '16 at 15:58
2

@AlvinfromDiaspar Yes, likely since other languages use `float` instead of `Float`, so it looks like that type/keyword instead of a variable name. – Ky - Mar 10 '17 at 21:34

hyouuu · Answer 2 · 2015-06-16T21:31:23.143

33

If you are as lazy as I am, in an Extensions.swift define the following:

extension Int {
  var f: CGFloat { return CGFloat(self) }
}

extension Float {
  var f: CGFloat { return CGFloat(self) }
}

extension Double {
  var f: CGFloat { return CGFloat(self) }
}

extension CGFloat {
  var swf: Float { return Float(self) }
}

Then you can do:

var someCGFloatFromFloat = 1.3.f
var someCGFloatFromInt = 2.f
var someFloatFromCGFloat = someCGFloatFromFloat.swf

edited Jun 16 '15 at 21:31

answered Nov 09 '14 at 16:47

hyouuu

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looks like a candidate for generic struct – μολὼν.λαβέ Mar 09 '17 at 19:37
@Ian I don't understand your question... an example? – hyouuu Apr 04 '17 at 08:45

score 13 · Answer 3 · answered Jun 10 '14 at 18:04

Usually, the best solution is to keep the type and use CGFloat, even in Swift. That's because CGFloat has different size on 32bit and 64bit machines.

Keyword as can be used only for dynamic casting (for subclasses), e.g.

class A {
}

class B : A {
}

var a: A = B()
var b: B = a as B

However, Double, Int, Float etc are not subclasses of each other, therefore to "cast" you have to create a new instance, e.g.

var d: Double = 2.0
var f: Float = Float(d) //this is an initialiser call, not a cast
var i: Int = Int(d) //this is an initialiser call, not a cast

Note that you can also use `as` for casting a generic type into a concrete type. For example, if you had a function that accepts a generic type that conforms to `BinaryInteger`, you can cast it to `Int` using `as?` or `as!`. — Peter Schorn, Aug 06 '20 at 10:02

Casting CGFloat to Float in Swift

3 Answers3