PHP Type Casting

Question

So I was asked as part of my homework to cast a floating point number to integer in PHP. Problem is that no such cast is possible according to php.net and I myself cannot find the notion behind the question.

Given the following:

$float = 1.92;
$float += 2;

It'll just substitute them resulting in 3.92 as an output.

As far as I could see the possible (or rather allowed) casts are as follows:

The casts allowed are:

(int), (integer) - cast to integer
(bool), (boolean) - cast to boolean
(float), (double), (real) - cast to float
(string) - cast to string
(array) - cast to array
(object) - cast to object
(unset) - cast to NULL (PHP 5)

Is it some sort of trick that they have presented us with or the task is invalid?

possible duplicate of [PHP unexpected result of float to int type cast](http://stackoverflow.com/questions/3385685/php-unexpected-result-of-float-to-int-type-cast) — , Jun 11 '14 at 21:13
@Mark Baker: Because PHP documentation does not say it could be casted. — Mike Fonder, Jun 11 '14 at 21:18
@MikeFonder You quoted it yourself in your post `The casts allowed are: (int), (integer) - cast to integer `: is ___cast to integer___ so difficult to recognise — Mark Baker, Jun 11 '14 at 21:19
Why is the question titled **PHP Type Casting** if you dont want to cast the value to an int? — RiggsFolly, Jun 11 '14 at 21:20

score 3 · Accepted Answer · answered Jun 11 '14 at 21:18

3

Was the task to round the float to the nearest whole number? In which case:

$float = 1.92;
$float += 2;

echo round($float);

outputs 4. Or a straight cast:

$float = 1.92;
$float += 2;

echo (int) $float;

outputs 3.

answered Jun 11 '14 at 21:18

Drumbeg

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I suppose the second example should be valid and accepted as a solution. I'll proceed with it. Thanks for your time :) – Mike Fonder Jun 11 '14 at 21:23

score 0 · Answer 2 · answered Jun 11 '14 at 21:22

0

What makes you think you can't cast float to int?

php > $float = 1.92;
php > var_dump($float);
float(1.92)
php > $int = 2 + (int)$float;
php > var_dump($int);
int(3)
php > $int2 = (int)(2 + $float);
php > var_dump($int2);
int(3)

answered Jun 11 '14 at 21:22

Marc B

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score 0 · Answer 3 · edited Oct 01 '20 at 09:05

0

You can always convert the float number to string like for your code

$float = 1.92;
$float +=2;
$int = (int)$float;
echo $int;

PHP always supports float to integer type casting.

edited Oct 01 '20 at 09:05

Martijn Pieters

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answered Jan 28 '17 at 00:48

Ankur Kumar Singh

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PHP Type Casting

3 Answers3