Division of two numbers not storing properly as a double in Java

Question

I declared a variable as a double in java from two figures and it doesn't seem to be coming up properly in the output. For instance, my runs figure was 18, the balls figure was 21, however when printed to screen, the strikerate variable only displayed as 0.0. Can anybody see my issue here? :)

    double strikerate = runs/balls;


    System.out.println(runs);
    System.out.println(balls);

    System.out.println(" ");
    System.out.println("Strikerate: " + strikerate);

what is the type of runs and balls – Rishi Dwivedi Jun 12 '14 at 05:22 — Rishi Dwivedi, Jun 12 '14 at 05:22
When you divide two integers you get an integer. – Peter Lawrey Jun 12 '14 at 07:03 — Peter Lawrey, Jun 12 '14 at 07:03

score 4 · Answer 1 · answered Jun 12 '14 at 05:20

4

int division will result in int value, you need to cast it to (double)

double strikerate = ((double)runs)/balls;

answered Jun 12 '14 at 05:20

jmj

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@immibis AVOID Answering in comment!! – akash Jun 12 '14 at 05:25

score 1 · Answer 2 · answered Jun 12 '14 at 05:22

1

do like this

 double strikerate = (double) runs/balls;

answered Jun 12 '14 at 05:22

Rishi Dwivedi

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Oh.. I see. But why ?? Try to explain why your code works. Mere code is not an answer. – Suresh Atta Jun 12 '14 at 05:23
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because int/int so... need to be cast into double – Rishi Dwivedi Jun 12 '14 at 05:24

Division of two numbers not storing properly as a double in Java

2 Answers2