get the last portion of the link using java regex

Question

I have an arraylist links. All links having same format abc.([a-z]*)/\\d{4}/

List<String > links= new ArrayList<>();
        links.add("abc.com/2012/aa");
        links.add("abc.com/2014/dddd");
        links.add("abc.in/2012/aa");

I need to get the last portion of every link. ie, the part after domain name. Domain name can be anything(.com, .in, .edu etc).

/2012/aa
/2014/dddd
/2012/aa

This is the output i want. How can i get this using regex? Thanks

score 3 · Answer 1 · edited May 23 '17 at 10:33

3

Some people, when confronted with a problem, think “I know, I'll use regular expressions.” Now they have two problems.

(see here for background)

Why use regex ? Perhaps a simpler solution is to use String.split("/") , which gives you an array of substrings of the original string, split by /. See this question for more info.

Note that String.split() does in fact take a regex to determine the boundaries upon which to split. However you don't need a regex in this case and a simple character specification is sufficient.

edited May 23 '17 at 10:33

Community

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answered Jun 12 '14 at 10:09

Brian Agnew

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+1 for nice solution and quote... but is it true the [quote is incomplete](http://www.rexegg.com/regex-humor.html) (second par, two-problem quote)? :) – zx81 Jun 12 '14 at 10:25

Braj · Answer 2 · 2014-06-12T15:01:18.077

2

Try with below regex and use regex grouping feature that is grouped based on parenthesis ().

\.[a-zA-Z]{2,3}(/.*)

Pattern description :

dot followed by two or three letters followed by forward slash then any characters

DEMO

Sample code:

Pattern pattern = Pattern.compile("\\.[a-zA-Z]{2,3}(/.*)");
Matcher matcher = pattern.matcher("abc.com/2012/aa");

if (matcher.find()) {
    System.out.println(matcher.group(1));
}

output:

/2012/aa

Note:

You can make it more precise by using \\.[a-zA-Z]{2,3}(/\\d{4}/.*) if there are always 4 digits in the pattern.

edited Jun 12 '14 at 15:01

answered Jun 12 '14 at 10:23

Braj

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what if the pattern is abc.edu? – Engineer Jun 12 '14 at 10:26
it mean he has to add all kind of url patterns in the list – Engineer Jun 12 '14 at 10:28

akash · Answer 3 · 2014-06-12T10:31:18.280

1

Use foreach loop to iterate over list.
Use substring and indexOf('/').

FOR EXAMPLE

String s="abc.com/2014/dddd";
System.out.println(s.substring(s.indexOf('/')));

OUTPUT

/2014/dddd

Or you can go for split method.

System.out.println(s.split("/",2)[1]);//OUTPUT:2014/dddd --->you need to add /

edited Jun 12 '14 at 10:31

answered Jun 12 '14 at 10:10

akash

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score 1 · Answer 4 · answered Jun 12 '14 at 10:20

1

String result = s.replaceAll("^[^/]*","");

s would be the string in your list.

answered Jun 12 '14 at 10:20

Kent

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score 1 · Answer 5 · answered Jun 12 '14 at 10:20

1

Some people, when confronted with a problem, think “I know, I'll use regular expressions.” Now they have two problems.

Why not just use the URI class?

output = new URI(link).getPath()

answered Jun 12 '14 at 10:20

Mikkel Løkke

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score 1 · Answer 6 · answered Jun 12 '14 at 10:22

1

Try this one and use the second capturing group

(.*?)(/.*)

answered Jun 12 '14 at 10:22

Esteban

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get the last portion of the link using java regex

6 Answers6