Apply all hash's value to integer if it could

Question

I want to get the buy_house_params, if values like "123" can be 123

if value is abc then keep it as original.

buy_house_params.each { |key, value| buy_house_params[key]=value.to_i }

But I still get the string type integer

{"user_id"=>"", "age"=>"28", "gender"=>"male", "monthly_income"=>"48000"}

Rails parses string into integers automatically based in activemodel information if that's your concern. — Jorge de los Santos, Jun 13 '14 at 02:43

score 0 · Accepted Answer · answered Jun 13 '14 at 02:44

Try this:

class String
  def is_number?
    true if Float(self) rescue false
  end
end

buy_house_params = {"user_id"=>"", "age"=>"28", "gender"=>"male", "monthly_income"=>"48000"}
buy_house_params.each{|k, v| buy_house_params[k] = v.to_i if v.is_number? }
=> {"user_id"=>"", "age"=>28, "gender"=>"male", "monthly_income"=>48000}

It will test to see if each hashmap value is numeric before converting it to an integer.

score 0 · Answer 2 · edited May 23 '17 at 12:05

You can use a regular expresion parse the string only if it matches the desired format: quoted integers.

class String
    def is_i?
       !!(self =~ /\A[-+]?[0-9]+\z/)
    end
end

Answered here:

Test if a string is basically an integer in quotes using Ruby?

Or you can test if it's an integer:

>> Integer "1"
=> 1
>> Integer "one"
ArgumentError: invalid value for Integer(): "one"

Ruby: checking if a string can be converted to an integer

Apply all hash's value to integer if it could

2 Answers2