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Is there any performance advantage for referring to an instance variable foo as this.foo as opposed to simply foo?

MC Emperor
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Gengar
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    Don't you think that if there was a difference, the compiler would resolve by itself? – Mephy Jun 13 '14 at 17:04
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    It slows down the compiler by a few nanoseconds and the programmer by up to a few seconds, depending on typing speed. Other than that: NO. – maaartinus Jun 13 '14 at 17:20

1 Answers1

2

There is no difference in terms of compiled bytecode or performance1.

Using the this.foo form is useful when there is a local shadowing foo in scope2 - in which case both forms do something different, so the above statement doesn't apply - but it otherwise has no effect.

1 See Does using the 'this' keyword affect Java performance?, which shows that the generated bytecode is identical; and closing for a duplicate!

2 See Java - when to use 'this' keyword and When to use "this" in Java for examples and in-depth explanations.

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user2864740
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