Is there any function returns only the real number without the floating point? For an example,
func(1.xxx)->1
func(52.xx)->52
func(0.xx)->0
Is there any function does so?
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Typecast it into Integer then you will get the decimal value.. – kalyan pvs Jun 14 '14 at 10:09
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have you try Math.round() ? – Haresh Chhelana Jun 14 '14 at 10:09
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`int a = (int) doble_value;` Just cast it to Integer. – user3145373 ツ Jun 14 '14 at 10:10
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@Haresh actually not I searched google but the results were not what ia m searching for – Amrmsmb Jun 14 '14 at 10:13
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@Elpharaoh - what exactly you want to do ? – user3145373 ツ Jun 14 '14 at 10:13
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@user3145373ツ i want only the real/integer number to be returned – Amrmsmb Jun 14 '14 at 10:15
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Simply casting to int would truncate everything past the decimal point.
float f1 = 10.345;
int i1 = (int) f1; // Gives 10
float f2 = 10.897;
int i2 = (int) f2; // Also gives 10
starf
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@Rogue That's correct for positive numbers. Negative numbers work a little differently. We are talking about truncating here. See http://math.stackexchange.com/questions/344815/how-do-the-floor-and-ceiling-functions-work-on-negative-numbers – starf Jun 14 '14 at 11:28
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You can do :
double d = 100.675;
System.out.println((int) d);
this gives you 100.
System.out.println(Math.round(d));
gives you 101.
You can also use :
new java.text.DecimalFormat("#").format(10.0); // => "10"
now the choice is yours that how you want to do and main thing depend on that what is your expected output is.
user3145373 ツ
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Yes I know, I have posted this first in comment then answers came of above. – user3145373 ツ Jun 14 '14 at 10:29