Pattern matching with Strings seperated by dots in Java

Question

I need to find strings that match a particular pattern. For example in the following condition:

if("1.6.1.1.60885.5".matches("1.6.1.1.n.5".replaceAll("n", "\\\\d{0,10}")))

then it should be true, since n can be any integer. 60885 is an integer. This works fine.

if("1.6.1.1.60885".matches("1.6.1.1.n.5".replaceAll("n", "\\\\d{0,10}")))

then it should be false. But I get this also as true.

I just need the n to be any integer but the dots position has to be considered. Can anyone suggest how can I achieve this.

If I use replaceAll("n", "\\d{0,10}"), then if("1.6.1.1.60885.5".matches("1.6.1.1.n.5".replaceAll("n", "\\d{0,10}"))) will give false instead of giving true. — yogi_bear, Jun 16 '14 at 10:30

score 2 · Accepted Answer · answered Jun 16 '14 at 10:04

2

matches("1\\.6\\.1\\.1\\.n\\.5",... )

The '.' is a wildcard and must be quoted.

(wildcard = "match any character")

answered Jun 16 '14 at 10:04

laune

1 Answers1