Just add the 'г. ' part.
/^\d\d?\.\d\d?\.\d\d\d?\d? ?'г\.'$/
Please note that that the regex actually doesn't validate dates. For example the '20.20.2020' is considered as valid date.
Edit for full validation:
You can use something like this:
/^((31[.]0?[13578]|1[02][.](18|19|20)[0-9]{2})|((29|30)[.](0?1|0?[3-9]|1[1-2])[.](18|19|20)[0-9]{2})|((0?[1-9]|1[0-9]|2[0-8])[.](0?[1-9]|1[0-2])[.](18|19|20)[0-9]{2})|((29)[.](0?2)[.](((18|19|20)(04|08|[2468][048]|[13579][26]))|2000))) 'г\.'$/
But as I said in the comment it's unreadable.
Also it's better to use "[0-9]" instead of "\d" because the last mean "all digits" not only 0123456789 but also these:
ZERO: 0٠۰߀०০੦૦୦௦౦೦൦๐໐0
ONE: 1١۱߁१১੧૧୧௧౧೧൧๑໑1
TWO: 2٢۲߂२২੨૨୨௨౨೨൨๒໒2
THREE: 3٣۳߃३৩੩૩୩௩౩೩൩๓໓3
FOUR: 4٤۴߄४৪੪૪୪௪౪೪൪๔໔4
FIVE: 5٥۵߅५৫੫૫୫௫౫೫൫๕໕5
SIX: 6٦۶߆६৬੬૬୬௬౬೬൬๖໖6
SEVEN: 7٧۷߇७৭੭૭୭௭౭೭൭๗໗7
EIGHT: 8٨۸߈८৮੮૮୮௮౮೮൮๘໘8
NINE: 9٩۹߉९৯੯૯୯௯౯೯൯๙໙9��
Source: Should I use \d or [0-9] to match digits in a Perl regex?