Dividing a string into a list of smaller strings of certain length

Question

If i have this string:

"0110100001100101011011000110110001101111"

How can I divide it at every eighth character into smaller strings, and put it into a list, so that it looks like this?:

['01101000','01100101','01101100','01101100','01101111']

So far, I can't figure out how this would be possible.

I should mention, since my strings are in binary so the length is always a multiple of 8.

You can easily modify the answers given on the duplicate to handle strings instead. — jonrsharpe, Jun 17 '14 at 15:30
@jonrsharpe I don't think the answers for that other question contain the most elegant way to solve the specific problem at hand. How easily adjustable those answers are depends on the python-experience of the OP. — timgeb, Jun 17 '14 at 15:41
@timgeb [This question](http://stackoverflow.com/q/9475241/3001761) is arguably closer, but is also closed as a duplicate! — jonrsharpe, Jun 17 '14 at 15:42
@timgeb I didn't realise you could close as duplicate of a duplicate! — jonrsharpe, Jun 17 '14 at 15:47
@jonrsharpe oh, you can? I wouldn't know. In case you were being sarcastic, I just would not have closed that other duplicate question as a duplicate to begin with. :) — timgeb, Jun 17 '14 at 15:49

timgeb · Accepted Answer · 2014-06-17T16:16:11.133

8

>>> mystr = "0110100001100101011011000110110001101111"
>>> [mystr[i:i+8] for i in range(0, len(mystr), 8)]
['01101000', '01100101', '01101100', '01101100', '01101111']

The solution uses a so called list comprehension (this seems to be a pretty decent tutorial) and is doing basically the same as Aleph's answer, just in one line.

edited Jun 17 '14 at 16:16

answered Jun 17 '14 at 15:31

timgeb

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If you are interested in how this answer works, google Python List Comprehension. – LexyStardust Jun 17 '14 at 15:34

score 3 · Answer 2 · answered Jun 17 '14 at 15:31

3

t=[]
for i in range(len(yourstring)/8):
    t.append(yourstring[i*8: (i+1)*8])

answered Jun 17 '14 at 15:31

Aleph

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score 3 · Answer 3 · edited Jun 17 '14 at 17:25

You can also use re

import re

In [21]: s="0110100001100101011011000110110001101111"

In [22]: re.findall('.{8}',s)
Out[22]: ['01101000', '01100101', '01101100', '01101100', '01101111']

As your strings only contain digits we can use . to match any character.

You can also explicitly use the \d{8} which matches 8 digits in a low.

In [23]: In [22]: re.findall('\d{8}',s)
Out[23]: ['01101000', '01100101', '01101100', '01101100', '01101111']

Dividing a string into a list of smaller strings of certain length

3 Answers3