How to get mm-dd-yyyy in DOS batch file?

Question

In a batch file I need to get a file from a folder that has today's date.

The problem is I can't get the batch date command to return the proper format.

I have this: echo %date:/=-%

But that always returns for example: Fri 06-20-2014

What's the proper call for just returning: 06-20-2014

Looked all over can't find.

Thanks!

possible duplicate of [How to get current datetime on Windows command line, in a suitable format for using in a filename?](http://stackoverflow.com/questions/203090/how-to-get-current-datetime-on-windows-command-line-in-a-suitable-format-for-us) — npocmaka, Jun 20 '14 at 19:51

score 10 · Accepted Answer · edited Jun 13 '22 at 11:49

10

This works independent of regional date/time format:

for /f %%I in ('wmic os get localdatetime ^|find "20"') do set dt=%%I
REM dt format is now YYYYMMDDhhmmss...
set dt=%dt:~4,2%-%dt:~6,2%-%dt:~0,4%
echo %dt%

edited Jun 13 '22 at 11:49

Ziemowit Zabawa

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answered Jun 20 '14 at 20:04

Stephan

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works too, thanks! accepting this one because it is independent. – user167908 Jun 21 '14 at 12:20

SachaDee · Answer 2 · 2018-09-06T16:18:28.977

8

set "$date=%date:~4%"
set "$date=%$date:/=-%"
echo %$date%

edited Sep 06 '18 at 16:18

answered Jun 20 '14 at 19:57

SachaDee

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How to get mm-dd-yyyy in DOS batch file?

2 Answers2